Order Description

My Major is Master of Molecular Imaging .

I have an assignment In MRI Advanced Techniques about
“Basic RF Pulse and Offset Independent Adiabaticity” .
I will send you the assignment paper , with the other file that has given to me .
– Please , before you start , read all the question carefully , and check on the example that will be included , the example is similar to mine but with a different way , so our tutor asked us to do it with more details and by Excel Program .

– Also, I’m not sure about the number of pages that I need , so I chose 3 pages .

Discussion between a student and the lecturer which could help:

For the y column I tried using the equations given in Tesmir and Bendall 2001 (I have it attached)
For amplitude modulatedy(B1) = Rfmax sech.beta(1-2t/Tp)
where beta=5.3
Tp= 10ms
Rfmax=100
t = the corresponding x cell
For the corresponding frequency
y(freq)=(bwdth/2)*[tanh.beta(1-2t/Tp)+s]
I used
s=0
bwdth=10 kHz = 10000 Hz
beta = 5.3
t= the corresponding x cell
Not sure if this is correct tho since my amplitude pulse looks gaussian rather than a standard sech function

This was for a full passage pulse btw. I can also mimic the rounded trapezoid structure by using two functions (I think this is cheating though) seen in the paper that is linked in the course materials by basically saying: TANH(x) then after x = 5, TANH(5.3*(1-2*(x-5)/10) – its the top image in the attachment. However the frequency doesnt end up like the image seen in the paper after squaring both functions and taking the integral (as Dr. Tesiram has said in the lecture). Maybe I am missing something?

By bandwidth I mean the frequency sweep of the pulse. For example, an amplitude only modulated pulse does not have a frequency sweep, thus its frequency is constant. A pulse with a frequency sweep will then be swept from negative off-resonance, through resonance and then positive off-resonance, or in the reverse direction. The bandwidth is then the extent of frequency sweep. So, a 50kHz bandwidth pulse will be swept from -25kHz off-resonance to 25kHz off-resonance.
. Vector diagrams should look like this diagram